```
- (void) layoutSubviews {
[super layoutSubviews];
CGFloat margin = 10;
UIEdgeInsets safeArea = self.pinObjc.safeArea;
logo.pinObjc.topInsets(safeArea).leftInsets(safeArea).width(100).aspectRatio().margin(margin).layout();
segmented.pinObjc.rightOfAligned(logo, VerticalAlignTop).rightInsets(safeArea).marginHorizontal(margin).layout();
textLabel.pinObjc.belowOfAligned(segmented, HorizontalAlignLeft).widthOf(segmented).pinEdges().marginTop(margin).sizeToFitType(FitWidth).layout();
separatorView.pinObjc.belowOfViewsAligned(@[logo, textLabel], HorizontalAlignLeft).rightToEdge(segmented.edge.right).height(1).marginTop(margin).layout();
}
```
:pushpin: This example is available in the Examples App. See example complete [source code](https://github.com/layoutBox/PinLayout/blob/master/Example/PinLayoutSample/UI/Examples/IntroObjectiveC/IntroObjectiveCView.m)
## Important notes about PinLayout's Objective-c interface
#### `pinObjc` property
The PinLayout's objective-c interface is available using the property `pinObjc` (instead of `pin` in Swift)
```
view.pinObjc.top().layout();
```
#### `layout()`
**Method:**
* **`layout()`**
When using the Objective-c interface, the `layout` method must be called explicitly to complete the view's layout. The method will execute PinLayout commands immediately. In Swift, PinLayout executes this method implicitly, it is not necessary to call it.
```
// Swift
view.pin.width(100)
// Objective-c
view.pinObjc.width(100).layout();
```